In the annual examination Ajay got 20% marks and failed by 50 marks. And in the same examination Abel got 40% marks and got 30 marks more than the minimum mark to pass. Find the maximum mark in the examination?
Here is the solution :
Let the maximum mark be x. Difference in percentage of marks = 20% Difference in mark = 80 x* 20/100 = 80
x = 400 marks.