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An aeroplane moving horizontally with a speed of the 720km/h drops a food pocket, while flying at a height of 396.9m the time taken by a food pocket to reach the ground and its horizontal range is*_*** _**__ Pls give The solution of the question

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Thank u Vishnu

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Vishnu

s=ut + 1/2gt^2 , here u=0

therefore , 396.6= 1/2(9.8)t^2

t^2=(396.9*2)/9.8 = 81, t=9
Distance covered in 9 sec = vt= (720*1000*9)/3600 = 1800 m

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.

.♥{🅰tHℹ®@}

Thank u Vishnu

1